Explanation of assembly code in x86

#include<stdio.h>
#include<string.h>
#include<stdlib.h>

int main(int argc, char *argv[]){
   char a[5];
   char b[10];
   strcpy(a,"nop");
   gets(b);
   printf("Hello there %s. Value in a is %s.\n",b,a);
   exit(0);
}

The first few lines of assembly output show:

push %ebp
mov %esp,%ebp
sub $0x28,%esp
mov $0x80c5b08,%edx
lea -0xd(%ebp),%eax
mov (%edx),%edx
mov %edx,(%eax)
lea -0x17(%ebp),%eax
mov %eax,(%esp)
call 0x8049c60 <gets>

I'm confused for a few reason. First, why do we do sub $0x28,%esp which accounts for 40 bytes if char *argv[] accounts for 8 bytes, int argc accounts for 4, a accounts for 8, and b accounts for 12 -> 8+4+8+12 = 32?

I'm also struggling to see where strcpy happens and what accounts for the two memory addresses $0x80c5b08 and 0x8049c60.